The equation of a circle which cuts the three circles x2 + y2 − 3x �

1.	The equation of a circle which cuts the three circles x2 + y2 − 3x − 6y + 14 = 0, x2 + y2 − x − 4y + 8 = 0 x2 + y2 + 2x − 6y + 9 = 0 orthogonally is –––––––––––––––
Answer» The equation of a circle which cuts the three circles $x^{2} + y^{2} - 3 x - 6 y + 14 = 0,$ $x^{2} + y^{2} - x - 4 y + 8 = 0$ $x^{2} + y^{2} + 2 x - 6 y + 9 = 0$ orthogonally is $- ------------- -$

The equation of a circle which cuts the three circles x2 + y2 − 3x − 6y + 14 = 0, x2 + y2 − x − 4y + 8 = 0 x2 + y2 + 2x − 6y + 9 = 0 orthogonally is –––––––––––––––

Answer»

The equation of a circle which cuts the three circles

$x^{2} + y^{2} - 3 x - 6 y + 14 = 0,$

$x^{2} + y^{2} - x - 4 y + 8 = 0$

$x^{2} + y^{2} + 2 x - 6 y + 9 = 0$

orthogonally is $- ------------- -$