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The equation of a plane containing the line of intersection of the planes 2x – y – 4 = 0 and y + 2z – 4 = 0 and passing through the point (1, 1, 0) is -(1) x – 3y – 2z = – 2(2) x – y – z = 0(3) x + 3y + z = 4(4) 2x – z = 2 |
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Answer» Correct option (2) x – y – z = 0 Explanation: Required equation of plane (2x – y – 4) + λ (y + 2z – 4) = 0 Required plane passes through (1, 1, 0) (2 – 1 – 4) + λ (1 + 0 – 4) = 0 λ = – 1 (2x – y – 4) – (y + 2z – 4) = 0 2x – 2y – 2z = 0 x – y – z = 0 |
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