The equation of a simple harmonic motion is given by y = 3 sin.(pi)/(2) (50 t-x), where x and y are in metres and t is in seconds, the ratio of maximum particle velocity to the wave velocity is

The equation of a simple harmonic motion is given by y = 3 sin.(pi)/(2

1.	The equation of a simple harmonic motion is given by y = 3 sin.(pi)/(2) (50 t-x), where x and y are in metres and t is in seconds, the ratio of maximum particle velocity to the wave velocity is
Answer» 25 m/s 30 m/s 50 m/s None of these Solution :The given wave equation is `y = 3 SIN .(pi)/(2)(50 t - x)` `implies ""y = 3 sin (25 pi t - (pi)/(2)x) ""...(i)` Comparing with standard equation `y = a sin (omegat - KX) ""...(ii)` `OMEGA=25pi, K = pi//2` Wave velocity, `v = (omega)/(k)=(25pi)/(pi//2)=50m//s`