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The equation of a transverse wave is given by y = 10 sin {pi (0.01 x - 2t)}where y and x are incm and t is in seconds. Its frequency is ………..

Answer»

`10 s^(-1)`
`2 s^(-1)`
`1 s^(-1)`
`0.01 s^(-1)`

Solution :Comparing with the standard equation y = `A sin (k X - omega t)` ,
we have `omega = 2pi`
Therefore , Frequency `F = (2pi)/(omega) = 1 s^(-1)`


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