The equation of a wave is given by `Y = A sin omega((x)/(v) -k)` where `omega` is the angular velocity and v is the linear velocity. The dimension of k isA. `[LT]`B. `[T]`C. `[T^(-1)]`D. `[T^(2)]`

The equation of a wave is given by `Y = A sin omega((x)/(v) -k)` where

1.	The equation of a wave is given by `Y = A sin omega((x)/(v) -k)` where `omega` is the angular velocity and v is the linear velocity. The dimension of k isA. `[LT]`B. `[T]`C. `[T^(-1)]`D. `[T^(2)]`
Answer» Correct Answer - B Dimensionally `k= (x)/(v) = ([L])/([LT^(-1)]) = [T^(1)]`

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The equation of a wave is given by `Y = A sin omega((x)/(v) -k)` where `omega` is the angular velocity and v is the linear velocity. The dimension of k isA. `[LT]`B. `[T]`C. `[T^(-1)]`D. `[T^(2)]`

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