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The equation of circum−circle of a ΔABC is x2+y2+3x+y−6=0.If A=(1,−2),B(−3,2) and the vertex C varies then the locus of ortho−centre of Δ ABC is a |
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Answer» The equation of circum−circle of a ΔABC is x2+y2+3x+y−6=0.If A=(1,−2),B(−3,2) and the vertex C varies then the locus of ortho−centre of Δ ABC is a |
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