Saved Bookmarks
| 1. |
The equation of current in a purely inductive circuit is 5sin (49 πt - 30°) . If the inductance is 30 mH then the equation for the voltage across the inductor, will be : {let π = 22/7}(A) 1.47 sin(49 πt - 30°) (B) 1.47 sin(49 πt + 60°) (C) 23.1sin(49 πt - 30°) (D) 23.1sin(49 πt + 60°) |
|
Answer» (D) 23.1sin(49 πt + 60°) V0 = i0 XL = i0 (WL) = (5) (49π) (30 x 10) = 23.1 Voltage will lead current by 90°. ∴ V = 23.1 sin (49 πt + 60°) |
|