1.

The equation of current in a purely inductive circuit is 5sin (49 πt - 30°) . If the inductance is 30 mH then the equation for the voltage across the inductor, will be : {let π = 22/7}(A) 1.47 sin(49 πt - 30°) (B) 1.47 sin(49 πt + 60°) (C) 23.1sin(49 πt - 30°) (D) 23.1sin(49 πt + 60°)

Answer»

(D) 23.1sin(49 πt + 60°)

V0 = i0 XL

= i0 (WL)

= (5) (49π) (30 x 10)

= 23.1

Voltage will lead current by 90°.

∴ V = 23.1 sin (49 πt + 60°)



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