InterviewSolution
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InterviewSolution
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The equation of line is ` 2x - 2 = 3y + 1 = 6z - 2 ` find its direction ratios and also find the vector equation of the line . |
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Answer» Given equation is ` 2x - 2 = 3y + 1 = 6z - 2 ` i.e. `(x -1)/((1)/(2)) = (y + (1)/(3))/((1)/(3)) = (z - (1)/(3))/((1)/(6))` The line passes through the point whose position vector is ` bar a ` . ` therefore vara = hati - (1)/(3) hatj + (1)/(3) hatk ` and direction ratios of line are ` (1)/(2), (1)/(3), (1)/(6) or 3,2,1`. ` therefore barb = 3hati + 2hatj + hatk ` Hence , vector equation of line is ` barr = bara + lambda barb ` `therefore barr = (hati - (1)/(3) hatj +(1)/(3) hatk) + lambda (3 hati + 2hatj + 3hatk)` . |
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