The equation of motion of a particle of mass `1g` is `(d^(2)x)/(dt^(2)) + pi^(2)x = 0`, where `x` is displacement (in m) from mean position. The frequency of oscillation is (in Hz)A. `1//2`B. `2`C. `5sqrt(10)`D. `1//5 sqrt(10)`

The equation of motion of a particle of mass `1g` is `(d^(2)x)/(dt^(2)

1.	The equation of motion of a particle of mass `1g` is `(d^(2)x)/(dt^(2)) + pi^(2)x = 0`, where `x` is displacement (in m) from mean position. The frequency of oscillation is (in Hz)A. `1//2`B. `2`C. `5sqrt(10)`D. `1//5 sqrt(10)`
Answer» Correct Answer - A `(d^(2)x)/(dt^(2)) = - pi^(2)x` Comparing with `(d^(2)x)/(dt^(2)) = - omega^(2)x` We have, `omega = pi` `:. 2pif = pi` `f = (1)/(2) Hz`.

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The equation of motion of a particle of mass `1g` is `(d^(2)x)/(dt^(2)) + pi^(2)x = 0`, where `x` is displacement (in m) from mean position. The frequency of oscillation is (in Hz)A. `1//2`B. `2`C. `5sqrt(10)`D. `1//5 sqrt(10)`

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