1.

The equation of projectile is `y = 16 x - (5 x^2)/(4)`. Find the horizontal range.

Answer» Standard equation of projection motion.
`y = x tan theta[1 - (x)/(R )]`
Given equation : `y = 16 x - (5 x^2)/(4) = 16 x [1 -(x)/(64//5)]`
By comparing above equations, `R = (64)/(5) = 12.8 m`.


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