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The equation of second degree `x^2+2sqrt2x+2y^2+4x+4sqrt2y+1=0` represents a pair of straight lines.The distance between them isa. 4b. `4/sqrt3`c. 2d. `2sqrt3`A. 1 unitsB. 2 unitsC. 3 unitsD. 4 units |
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Answer» Correct Answer - B Here, `h = sqrrt(2) , g =2 , a = 1 , c = 1,b =2 , f = 2sqrt(2)` `therefore ` Distance `= 2 sqrt((g^(2) - ac)/(a(a+b)))` ` = 2sqrt((4-1)/(1(1+2))) = 2` units |
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