The equation of SHM of a particle is \(\frac{d^2y}{dt^2}\) + ky = 0,

1.	The equation of SHM of a particle is \(\frac{d^2y}{dt^2}\) + ky = 0, Where k is a positive constant. The time period of motion is given by ...(a) \(\frac{2π}{\sqrt k}\)(b) \(\frac{2π}{k}\)(c) \(\frac{k}{2π}\)(d) \(\frac{\sqrt k}{2π}\)
Answer» Correct answer is (a) \(\frac{2π}{\sqrt k}\) Here k is same as ω²

The equation of SHM of a particle is \(\frac{d^2y}{dt^2}\) + ky = 0, Where k is a positive constant. The time period of motion is given by ...(a) \(\frac{2π}{\sqrt k}\)(b) \(\frac{2π}{k}\)(c) \(\frac{k}{2π}\)(d) \(\frac{\sqrt k}{2π}\)

Answer»

Correct answer is (a) \(\frac{2π}{\sqrt k}\)

Here k is same as ω²

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The equation of SHM of a particle is \(\frac{d^2y}{dt^2}\) + ky = 0, Where k is a positive constant. The time period of motion is given by ...(a) \(\frac{2π}{\sqrt k}\)(b) \(\frac{2π}{k}\)(c) \(\frac{k}{2π}\)(d) \(\frac{\sqrt k}{2π}\)

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