The equation of tangent to the parabola `y^2 = 9x`, which pass through

1.	The equation of tangent to the parabola `y^2 = 9x`, which pass through the point (4, 10) is
Answer» Equation of a tangent to a parabola is given by , `y = mx+a/m->(1)` In the given parabola, `y^2 = 9x`, `4a = 9=> a = 9/4` Putting value of `a` in (1), `y = mx+9/(4m)->(2)` As the given tangent is passing through point `(4,10)`, `:. 10 = 4m+9/(4m)` `=>16m^2-40m + 9 = 0` `=>16m^2-36m-4m+9 = 0` `=>4m(4m-9)-1(4m-9) = 0` `=>(4m-9)(4m-1/4) = 0` `=> m = 9/4 and m = 1/4` When `m = 9/4`, required equation will be, `y = 9/4x+1 => 4y = 9x+4` When `m = 1/4`, required equation will be, `y = 1/4x+9 => 4y = x+36`

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The equation of tangent to the parabola `y^2 = 9x`, which pass through the point (4, 10) is

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