

InterviewSolution
Saved Bookmarks
1. |
The equation of the bisector of the obtuse angle between the lines `x-2y+4=0` and `4x-3y+2=0` is |
Answer» Equation of bisectors `(x-2y+4)/sqrt5=(4x--3y+2)/sqrt(4^2+3^2)` `sqrt5x-2sqrt5y+4sqrt5=4x-3y+2` `y(3-2sqrt5)+x(sqrt5-4)+4sqrt5-2=0` `m(beta_1)=(4-sqrt5)/(3-2sqrt5)` this will be negative So, this is obtuse. `(x-2y+4)/sqrt5=-(4x--3y+2)/sqrt(4^2+3^2)` In this case it will be positive So, this is acue. . |
|