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The equation of the circle concentric with the circle `x^(2) + y^(2) - 6x - 4y - 12 =0` and touching y axisA. `x^(2) + y^(2) - 6x - 4y + 4 =0`B. `x^(2) + y^(2) - 6x - 4y + 9 =0`C. `x^(2) + y^(2) - 6x - 4y - 4 =0`D. `x^(2) + y^(2) - 6x - 4y - 9 =0` |
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Answer» Correct Answer - A Given equation of circle `x^(2) + y^(2) - 6x - 4y - 12 = 0` Centre of circle (i) is (3,2) Equation of circle concentric with circle (i) and touching the Y-axis is `(X - 3)^(2) + (y -2)^(2) = (3)^(2)` `implies x^(2) + 9 - 6x + y^(2) + 4 - 4y = 9` `implies x^(2) + y^(2) - 6x - 4y + 4 = 0` |
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