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The equation of the circle drawn with the focus of the parabola `(x - 1)^2 - 8 y = 0` as its centre touching the parabola at its vertex is: |
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Answer» equation of parabola `(x-1)^2=8y`=4*2*y -(1) so, a=2 `x^2`=4ay putting in eq(1) x-1=0 x=0 y=0 vertex will be V(1,0) center of circle will be=(1,2) r=a=2 eqation of circle `(x-1)^2+(y-2)^2=2^2` `x^2-2x=1=y^2-4y=4=4` `x^2=y^2-2x-4y+1=0` |
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