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The equation of the hyperbola with vertices `(3,0)` and `(-3,0)` and semi-latursrectum `4`, is given byA. `4x^(2)-3y^(2)+36=0`B. `4x^(2)-3y^(2)+12=0`C. `4x^(2)-3y^(2)-36=0`D. none of these |
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Answer» We have, `a=3` and `(b^(2))/(a)=4impliesb^(2)=12`. Hence, the equation of the hyperbola is `(x^(2))/(9)-(y^(2))/(12)=1implies4x^(2)-3y^(2)=36` |
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