1.

The equation of the hyperbola with vertices `(3,0)` and `(-3,0)` and semi-latursrectum `4`, is given byA. `4x^(2)-3y^(2)+36=0`B. `4x^(2)-3y^(2)+12=0`C. `4x^(2)-3y^(2)-36=0`D. none of these

Answer» We have,
`a=3` and `(b^(2))/(a)=4impliesb^(2)=12`.
Hence, the equation of the hyperbola is
`(x^(2))/(9)-(y^(2))/(12)=1implies4x^(2)-3y^(2)=36`


Discussion

No Comment Found

Related InterviewSolutions