The equation of the image of the circle `x^2+y^2+16x-24y+183=0` by the line mirror `4x+7y+13=0` is :

The equation of the image of the circle `x^2+y^2+16x-24y+183=0` by the

1.	The equation of the image of the circle `x^2+y^2+16x-24y+183=0` by the line mirror `4x+7y+13=0` is :
Answer» `x^2+y^2+16x-24y+183=0` `x^2+16x+64-64+y^2-24y+144-144+183=0` `(x+8)^2+(y-12)^2+183-208=0` `(x+8)^2+(y-12)^2-25=5^2` Center(-8,12) `4x+7y+13=0-(1)` `7x+4y+k=0` `-56+48+k=0` `k=8` `7x+4y+8=0-(2)` From equation 1 and 2 `y=325/65=5` `y=5` `4x+7y+13=0` 9`4x+35+13=0` `x=-12` (-8,12),(-12,5),(h,k) `(-8+h)/2=-12` `h=-16` `(12+k)/2=5` `k=-2` (-16,-2) `(x+16)^2+(y+2)^2=25` `x^2+y^2+32x+4y+256+4-25=0` `x^2+y^2+32x+4y+235=0`.

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