1.

The equation of the plane passing through the points A(0,-1,0), B(2,1,-1) and C(1,1,1) is given byA. `(4x+3y-2z-3)=0`B. `4x-3y+2z+3=0`C. `4x-3y+2z-3=0`D. none of these

Answer» Correct Answer - c
Here `(x_(1)=0, y_(1)=-1, z_(1)=0), (x_(2)=2,y_(2)=1,z_(2)=-1))` and `(x_(3)=1, y_(3)=1, z_(3)=1)`.
So, the required equation of the plane is
`|{:(x-x_(1),y-y_(1),z-z_(1)),(x_(2)-x_(1),y_(2)-y_(1),z_(2)-z_(1)),(x_(3)-x_(1),y_(3)-y_(1),z_(3)-z_(1)):}|=0`
`|{:(x-0,y+1,z-0),(2-0,1+1,-1-0),(1-0,1+1,1-0):}|=0 rArr |{:(x,y+1,z),(2,2,-1),(1,2,1):}|=0`
`rArr x(2+2)-(y+1)(2+1)+z(4-2)=0`.
`rArr 4x-3(y+1)+2z=0 rArr 4x-3y+2z-3=0`.


Discussion

No Comment Found