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The equation of the tangent parallel to `y=x` drawn to `(x^(2))/(3)-(y^(2))/(2)=1`, isA. `x-y+1=0`B. `x-y+2=0`C. `x-y+3=0`D. `x-y-2=0` |
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Answer» Let `y=x+c` be the required tangent. Then, `c^(2)=3xx1^(2)-2impliesc=+-1` [ Using `c^(2)=a^(2)m^(2)-b^(2)`] Hence required tangents are `y=x+-1`. |
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