The equation to the perpendicular from the point `(alpha, beta gamma)` to the plane `ax+by+cz+d=0` isA. x + y+ z = abcB. `a(x-alpha)+b(y-beta)+c(z-gamma)=0`C. `a(x-alpha)+b(y-beta)+c(z-gamma)=abc`D. `(x-alpha)/(a)=(y-beta)/(b)=(z-gamma)/(c)`

The equation to the perpendicular from the point `(alpha, beta gamma)`

1.	The equation to the perpendicular from the point `(alpha, beta gamma)` to the plane `ax+by+cz+d=0` isA. x + y+ z = abcB. `a(x-alpha)+b(y-beta)+c(z-gamma)=0`C. `a(x-alpha)+b(y-beta)+c(z-gamma)=abc`D. `(x-alpha)/(a)=(y-beta)/(b)=(z-gamma)/(c)`
Answer» Correct Answer - D

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The equation to the perpendicular from the point `(alpha, beta gamma)` to the plane `ax+by+cz+d=0` isA. x + y+ z = abcB. `a(x-alpha)+b(y-beta)+c(z-gamma)=0`C. `a(x-alpha)+b(y-beta)+c(z-gamma)=abc`D. `(x-alpha)/(a)=(y-beta)/(b)=(z-gamma)/(c)`

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