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The equation `(x)^(2)=[x]^(2)+2x` where `[x]` and `(x)` are the integers just less than or equal to `x` and just greater than or equal to `x` respectively, then number of values of `x` satisfying the given equationA. `0`B. `1`C. `2`D. infinite |
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Answer» Correct Answer - D Case -I : If `xepsilonI` then `(x)=[x]` `:.` equationn becomes `x=0` Case II: If `x!inI` `:.` then `(x)=[x]+1` then equation becomes `x=[x]+1/2` `=n+1/2,"n" epsilonI` |
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