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The equation `x-y=4 and x^2+4xy+y^2=0` represent the sides ofA. an equilateral triangleB. a right - angled triangleC. an isosceles triangleD. None of these |
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Answer» Correct Answer - 1 Acute angle between the linens `x^(2)+4xy+y^(2)=0` is `tan^(-1){(2sqrt(4-1))//(1+1)}=tan^(-1)sqrt(3)=pi//3`. the angle bisectors of `x^(2)+4xy+y^(2)=0`are given by `(x^(2)-y^(2))/(1-1)=(xy)/(2)` or `x^(2)-y^(2)=0orx=+-y` As `x+y=0` is perpendicular to `x-y=4` , the given triangle is isosceles with vertical angle equal to `pi//3`. Hence , it is an equilateral triangle. |
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