The equilibrium constant at 25∘ C for the reaction Fe2++Ag+⇌Fe3++A – InterviewSolution

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1.	The equilibrium constant at 25∘ C for the reaction Fe2++Ag+⇌Fe3++Ag is:Given E0Ag+/Ag=0.7998 V and E0Fe3+/Fe2+=0.771 V, log 2 =0.30, log 3 = 0.48, 2.303RTF=0.06
Answer» The equilibrium constant at $25^{\circ} C$ for the reaction $F e^{2 +} + A g^{+} ⇌ F e^{3 +} + A g$ is: Given $E_{A g^{+} / A g}^{0} = 0.7998 V a n d E_{F e^{3 +} / F e^{2 +}}^{0} = 0.771 V$ , log 2 =0.30, log 3 = 0.48, $\frac{2.303 R T}{F} = 0.06$

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