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The equilibrium constant for a gaseous reversible reaction at 200°C is 1.64 × 103 atm2.Calculate ΔG0 for the reaction. |
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Answer» Given : Equilibrium constant = KP = 1.64 × 103 atm2 Temperature = T = 273 + 200 = 473 K ΔG0 = ? ΔG0 = -2.303 RTlog10Kp = – 2.303 × 8.314 × 473 × log101.64 × 103 = – 2.303 × 8.314 × 473 × (3.2148) = -29115 J = -29.115 kJ ∴ ΔG0 = -29.115 kJ |
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