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The equilibrium constant for a reaction is 2. What will be the value of ∆G°? (R = 8.314 J K-1 mol-1 , T = 400K) |
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Answer» Given, K = 2 R = 8.314 JK−1 mol−1 T = 400 K ∆G° = ? ∵ ∆G° = −2.303 RT log K = −2.303 × 8.314 × 400 × log 2 = −2.303 × 8.314 × 400 × 0.3010 = −2305.31 J mol−1 = −2.05 kJ mol−1 |
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