1.

The equilibrium constant for a reaction is 2. What will be the value of ∆G°? (R = 8.314 J K-1 mol-1 , T = 400K)

Answer»

Given, K = 2

R = 8.314 JK−1 mol−1

T = 400 K

∆G° = ?

∵ ∆G° = −2.303 RT log K

= −2.303 × 8.314 × 400 × log 2

= −2.303 × 8.314 × 400 × 0.3010

= −2305.31 J mol−1

= −2.05 kJ mol−1



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