The equilibrium constant for the following reaction at 298K is expressed as `x xx10^(y)` `2Fe^(3+)+2I^(-)to2Fe^(2+)+I_(2),E_(cell)^(@)=0.235V` The value of y is.

The equilibrium constant for the following reaction at 298K is express

1.	The equilibrium constant for the following reaction at 298K is expressed as `x xx10^(y)` `2Fe^(3+)+2I^(-)to2Fe^(2+)+I_(2),E_(cell)^(@)=0.235V` The value of y is.
Answer» For the given reaction, n=2 `E_(cell)^(@)=(0.0591)/(2)logK therefore0.235=(0.0591)/(2)logK` or `logK=7.9526` or `K=8.966xx10^(7)`.

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The equilibrium constant for the following reaction at 298K is expressed as `x xx10^(y)` `2Fe^(3+)+2I^(-)to2Fe^(2+)+I_(2),E_(cell)^(@)=0.235V` The value of y is.

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