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The equilibrium constant for the reaction `CaSO_(4).H_(2)O(s)hArr CaSO_(4).3H_(2)O(s)+2H_(2)O(g)` is equal toA. `([CuSO_(4).5H_(2)O][H_(2)O]^(2))/([CuSO_(4).5H_(2)O])`B. `([CuSO_(4).3H_(2)O])/([CuSO_(4).5H_(2)O])`C. `[H_(2)O]^(2)`D. `[H_(2)O]` |
Answer» Correct Answer - C |
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