1.

The equilibrium constant `K_(c)` for the following reaction at `842^(@)`C is `7.90xx10^(-3)`. What is `K_(p)`at same temperature ?` (1)/(2)F_(2(g)) hArr F_(g)`A. `8.64xx10^(5)`B. `8.26xx10^(-4)`C. `7.90xx10^(-2)`D. `7.56xx10^(-2)`

Answer» Correct Answer - D
`K_(P)=(7.9xx10^(-3))xx(0.0821xx115)^(0.5)`
`K_(P)=7.56xx10^(-2)`


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