The equilibrium constant (K) for the reaction `Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s)`, will be [Given, `E_(cell)^(@)=0.46 V`]A. `K_(C) = AL (15.6)`B. `K_(C) = AL(2.5)`C. `K_(C) = AL (1.5)`D. `K_(C) = AL (12.2)`

The equilibrium constant (K) for the reaction `Cu(s)+2Ag^(+) (aq) rarr

1.	The equilibrium constant (K) for the reaction `Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s)`, will be [Given, `E_(cell)^(@)=0.46 V`]A. `K_(C) = AL (15.6)`B. `K_(C) = AL(2.5)`C. `K_(C) = AL (1.5)`D. `K_(C) = AL (12.2)`
Answer» Correct Answer - A `E^(@) = (0.0592)/(n) "log" K_(C)` `therefore log K_(C) = (E^(@) xx n)/(0.0592) = (0.46 xx 2 )/(0.0592) = 15.6` `therefore K_(C) = AL (15.6)`

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