InterviewSolution
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InterviewSolution
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The equilibrium constant `K_p` for the reaction `AhArr2B` is related to the degree of dissociation `(alpha)` of A and total pressure `P` asA. `(4alpha^2P)/(1-alpha)`B. `(4alpha^2P^2)/(1-alpha)`C. `(4alpha^2P)/(1-alpha^2)`D. `(4alpha^2P^2)/(1-alpha^2)` |
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Answer» Correct Answer - C `{:(,A hArr 2B),("Initial moles","1 0"),("Change",-alpha+2alpha),("Equilibrium moles",bar(1-alpha " 2"alpha)):}` Partial pressure =(Mole fraction)(Total pressure) Mole fraction = Moles/Total moles `n_A=1-alpha`, `n_B=2alpha`, and `n_t=(1-alpha)+(2alpha)=1+alpha` `:. P_A=((1-alpha)/(1+alpha))P`, `P_B=((2alpha)/(1+alpha))P` |
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