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The equilibrium constant `K_(P)` for the reaction `N_(2)O_(4)(g) hArr 2NO_(2)(g)` is `4.5 atm`. What would be the average molar mass (in `g//mol`) of an equilibrium mixture at a total pressure of `2 atm` of `N_(2)O_(4)` and `NO_(2)` formed by the dissociation of pure `N_(2)O_(4)` ?A. `69`B. `57.5`C. `80.5`D. `85.5` |
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Answer» Correct Answer - B `K_(P) = (4prop^(2))/(1 - prop^(2)) P` `P = 2 atm , K_(P) = (9)/(2)` `prop =` degree of dissociation of `N_(2)O_(4)(g)` `25prop^(2) = 9 , prop = (3)/(5) = 0.6` `prop = (M_(t) - M_(mix))/((n-1)M_(mix))` `M_(exp) = (92)/(1 + 0.6) = 57.5 g//mol` |
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