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InterviewSolution
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The equilibrium constant, Kp for the reaction2SO2(g) + O2(g)-2503(g)is 4.0 atm at 1000 K. What would be the partial pressure of O2 if at equilibrium the amount of So2 andSO3 is the same?(1) 16.0 atm(2) 0.25 atm(3) 1 atm(4) 0.75 atm |
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Answer» Kp=p[SO3]²/p[SO2]² p[O2] Since, amount of SO3 and SO2 is same at equilibrium.Therefore partial pressure is also same .So, p[SO3] and p[SO2] will be cancelled out through division.Hence,Kp=1/p[O2]4=1/p[O2]p[O2]=1/4 =0.25 atm |
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