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The equilibrium constant of a reaction at 298 K is `5xx10^(-3)` and at 1000 K is `2xx10^(-5)`. What is the sign of `DeltaH` for the reactionA. `DeltaH=0`B. `DeltaH` is negativeC. `DeltaH` is positiveD. None of these |
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Answer» Correct Answer - B Equilibrium constant decreases with temperature and `DeltaH` also decreases so it is -ve. |
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