The equilibrium constant of the following redox rection at 298 K is `1 xx 10^(8)` `2Fe^(3+) (aq.) +2I^(-) (aq.) hArr 2Fe^(2+)(aq.) +I_(2) (s)` If the standard reducing potential of iodine becoming iodide is +0.54 V. what is the standard reduction potential of `Fe^(3+)//Fe^(2+)` ?A. `+ 1.006 V`B. `-1.006 V`C. `+ 0.77 V`D. `-0.77 V`

The equilibrium constant of the following redox rection at 298 K is `1

1.	The equilibrium constant of the following redox rection at 298 K is `1 xx 10^(8)` `2Fe^(3+) (aq.) +2I^(-) (aq.) hArr 2Fe^(2+)(aq.) +I_(2) (s)` If the standard reducing potential of iodine becoming iodide is +0.54 V. what is the standard reduction potential of `Fe^(3+)//Fe^(2+)` ?A. `+ 1.006 V`B. `-1.006 V`C. `+ 0.77 V`D. `-0.77 V`
Answer» Correct Answer - C `E^(@)=0.059/n log_(10) K` `=0.059/2 log_(10) 10^(8)=0.236` `E_(cell)^(@)=E_("Reduced species")^(@)-E_("Oxidised species")^(@)` `0.236=E_(Fe^(3+)//Fe^(2+))^(@)-0.54` `E_(Fe^(3+)//Fe^(2+))^(@)=0.77 V`

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