InterviewSolution
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InterviewSolution
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The equilibrium constant of the following redox rection at 298 K is `1 xx 10^(8)` `2Fe^(3+) (aq.) +2I^(-) (aq.) hArr 2Fe^(2+)(aq.) +I_(2) (s)` If the standard reducing potential of iodine becoming iodide is +0.54 V. what is the standard reduction potential of `Fe^(3+)//Fe^(2+)` ?A. `64.2`B. `51.0`C. `48.4`D. `25.5` |
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Answer» Correct Answer - B No. of equivalent of copper (II) salt = No. of equivalent of Iodine =No. of equivalents of hypo `rArr` No. of equivalent of copper (II) salt `= 24.5 xx 0.1 = 2.45` No. of milli moles of copper (II) salt `=2.45` Weight of copper in copper (II) salt `=2.45 xx 63.5 xx 10^(-3) = 0.1556g` `0.305g` of copper (II) salt contain `=0.1556g` of Cu `:. %` copper `=(0.1556)/(0.305) xx 100 = 51%` |
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