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The equilibrium constant of the reactionH2(g) + l2(g) ⇌ 2Hl(g) is 57 at 700 K.Now, give the equilibrium constants for the following reactions at the same temperature:(i) 2HI(g) ⇌ H2(g) + I2(g)(i) 4HI(g) ⇌ 2H2(g) + 2I2(g)(i) HI(g) ⇌ 1/2H2(g) + 1/2 I2(g) |
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Answer» (i) K'c = \(\frac{1}{K_c}=\frac{1}{57}\) = 0.0175 (ii) K'''c = K2c = (57)2 = 3249 (ii) K'''c = (Kc)1/2 = (57)1/2 = 7.55 |
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