The equivalent conctance at infinite dilution of the salt MX is 160.84 `ohm^(-1)cm^(2)eq^(-1)`. If the transport number of `M^(+)` is 0.40, calculate the ionic mobility of the ion.

The equivalent conctance at infinite dilution of the salt MX is 160.84

1.	The equivalent conctance at infinite dilution of the salt MX is 160.84 `ohm^(-1)cm^(2)eq^(-1)`. If the transport number of `M^(+)` is 0.40, calculate the ionic mobility of the ion.
Answer» Ionic conductance of ion=Transport no. of that ion`xx(AA)_(eq)^(@)` of strong electrolyte containing that ion `=(1-0.40)xx160.84=96.504` Ionic mobility`=("Ionic conductance")/(96,500)=(96.504)/(96,500)=10^(-3)`.

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