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The equivalent conductance of `M//32` solution of a weak monobasic acid is `8.0 ` and at infinite dilution is `400 `. The dissociation constant of this acid is :A. `1.25 xx 10^(-6)`B. `6.25 xx 10^(-4)`C. `1.25 xx 10^(-4)`D. `1.25 xx 10^(-5)` |
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Answer» Correct Answer - D Given , `Lambda = 8 ` mho `cm^(2)` `Lambda_(0) = 400 mho cm^(2)` Degree of dissociation , `alpha = (Lambda)/(Lambda_(0)) implies alpha = (8)/(400) = 2 xx 10^(-2)` Dissociation constant , `K = C alpha^(2)` Given , C = M/32 `therefore K = (1)/(32) xx 2 xx 10^(-2) xx 2 xx 10^(-2)` `K = 1.25 xx 10^(-5)` |
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