1.

The equivalent conductance of solution is …… . [If cell constant is `1.25 cm^(-1)` and resistance of `N//10` solution is `2.5xx10^(3) Omega`].A. `2.5 Omega^(-1) cm^(2)" equiv"^(-1)`B. `2.5 Omega^(-1) cm^(-2)" equiv"^(-1)`C. `50 Omega^(-1) cm^(2)" equiv"^(-1)`D. `5.0 Omega^(-1) cm^(2)" equiv"^(-1)`

Answer» Correct Answer - D
`k=("Cell constant")/("Resistance")=1.25/(2.5xx10^(3))=5xx10^(-4) Omega^(-1) cm^(-1)`
Equivalent conductance `=(kxx1000)/(M)`
`=(5xx10^(-4) xx1000)/(1//10)`
`=5Omega^(-1) cm^(2)" equiv"^(-1)`


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