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The equivalent constant of the reaction: `Cu(s)+2Ag^(+)(aq.) rarr Cu^(2+)(aq.)+2Ag(s)` `E^(@)=0.46 V` at `298 K`,is:A. `2.0 xx 10^(10)`B. `4.0xx10^(10)`C. `4.0xx10^(15)`D. `2.4xx10^(10)` |
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Answer» Correct Answer - C K= antilog `[(nE^(@))/0.059]=` antilog `[(2xx0.46)/0.059]` = antilog 15.593 `=3.9xx10^(15)` `~~ 4xx10^(15)` |
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