The equivalent mass of KMnO4 in alkaline medium is a.31.6 b.52.7 c.79.

1.	The equivalent mass of KMnO4 in alkaline medium is a.31.6 b.52.7 c.79.d.158
Answer» Answer: (b) In acidic medium the number of electrons involved are 5. Mno₄ + 8H+ + 5e– → Mn²⁺ + 4H₂O Eq. mass of KMnO₄ = 158/ 5 =31.6 In basic medium the number of electrons involved are 3. Mno₄ + 2H₂O+ + 3e– → MnO₂ + 4OH- Eq. mass of KMnO₄ = 158/ 3 = 52.7 Equivalent mass of KMnO₄ in acidic and alkaline medium is 31.6 and 52.7 respectively.

The equivalent mass of KMnO4 in alkaline medium is a.31.6 b.52.7 c.79.d.158

Answer»

Answer: (b)

In acidic medium the number of electrons involved are 5.

Mno₄ + 8H+ + 5e– → Mn²⁺ + 4H₂O

Eq. mass of KMnO₄ = 158/ 5 =31.6

In basic medium the number of electrons involved are 3.

Mno₄ + 2H₂O+ + 3e– → MnO₂ + 4OH-

Eq. mass of KMnO₄ = 158/ 3 = 52.7

Equivalent mass of KMnO₄ in acidic and alkaline medium is 31.6 and 52.7 respectively.