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The equivalent relation for given circuit will be(a) 1/l1 + 1/L2(b) L1 + L2 - 2M (c) L1 + L2 + 2M (d) L1 + L2 + M |
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Answer» (c) L1 + L2 + 2M For inductors in series Leq = L1 + L2 Due to mutual inductance Leq = L1 + L2 + 2M |
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