1.

The equivalent relation for given circuit will be(a) 1/l1 + 1/L2(b) L1 + L2 - 2M (c) L1 + L2 + 2M (d) L1 + L2 + M

Answer»

(c) L1 + L2 + 2M 

For inductors in series

Leq = L1 + L2

Due to mutual inductance

Leq = L1 + L+ 2M



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