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The equivalent weight of a metal is 9 and vapour density of its chloride is 59.25. The atomic weight of metal isA. 23.9B. 27.3C. 36.3D. 48.3 |
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Answer» Correct Answer - A Given equivalent weight of metal `=9` Vapour density of metal chloride `=59.25` `:.` molecular weight of metal chloride `=2xxV.D=2xx59.25=118.5` `:.` valency of metal `=("molecular weight of metal chloride")/("equivalent weight of metal + 35.5")` Valency of metal `=118.5/(9+35.5)=118.5/44.5=2.66` Therefore atomic weight of the metal = equivalent weight `xx` valency `=9xx2.66=23.9`. |
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