1.

The equivalent weight of H3PO4 in the following reaction is\mathrm{H}_{3} \mathrm{PO}_{4}+\mathrm{Ca}(\mathrm{OH})_{2} \longrightarrow \mathrm{CaHPO}_{4}+2 \mathrm{H}_{2} \mathrm{O}

Answer»

EQUIVALENT MASS IS SAME FOR ALL THE REACTION.

MOLECULAR MASS = 3 * 1 + 1 * 31 + 4 * 16

= 3 + 31 + 64 = 98

EQUIVALENT MASS = MOLECULAR MASS / NO. OF REPLACEABLE HYDROGEN ATOMS

= 98 /2

= 49



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