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The equivalent weight of H3PO4 in the following reaction is\mathrm{H}_{3} \mathrm{PO}_{4}+\mathrm{Ca}(\mathrm{OH})_{2} \longrightarrow \mathrm{CaHPO}_{4}+2 \mathrm{H}_{2} \mathrm{O} |
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Answer» EQUIVALENT MASS IS SAME FOR ALL THE REACTION. MOLECULAR MASS = 3 * 1 + 1 * 31 + 4 * 16 = 3 + 31 + 64 = 98 EQUIVALENT MASS = MOLECULAR MASS / NO. OF REPLACEABLE HYDROGEN ATOMS = 98 /2 = 49 |
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