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The equivalent weight of`KMnO_(4)` (formula weight M) when it is used as an oxidant in neural medium isA. MB. `M/2`C. `M/3`D. `M/5` |
Answer» Correct Answer - C In neutral medium `MnO_4^(-) + 2H_2O + 3e^(-) to MnO_2 + 4OH^(-)` `therefore `Equivalent weight is `"Molecular weight"/3` |
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