The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted toA. `Mn_(2)O_(3)`B. `MnO_(4)^(-)`C. `MnO_(2)`D. `MnO_(4)^(2-)`

The equivalent weight of `MnSO_(4)` is half its molecular weight when

1.	The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted toA. `Mn_(2)O_(3)`B. `MnO_(4)^(-)`C. `MnO_(2)`D. `MnO_(4)^(2-)`
Answer» Correct Answer - C Equivalent weight `=(molar mass)/("change in ON")=(M)/(2)` Thus, change in oxidation number `=2units` Change in `O.N.` (`a`) `underset(+2)underset(uarr)(MnSO_(4)) rarr underset(+3)underset(uarr)(Mn_(2)O_(3)) 1 unit E=(M)/(1)` (`b`) `underset(+2)underset(uarr)(MnSO_(4)) rarr underset(+4)underset(uarr)(MnO_(2)) 2 unit E=(M)/(2)` (`c`) `underset(+2)underset(uarr)(MnSO_(4)) rarr underset(+7)underset(uarr)(MnO_(4)^(-)) 5 unit E=(M)/(5)` (`d`) `underset(+2)underset(uarr)(MnSO_(4)) rarr underset(+6)underset(uarr)(MnO_(4)^(2-)) 4 unit E=(M)/(4)`

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The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted toA. `Mn_(2)O_(3)`B. `MnO_(4)^(-)`C. `MnO_(2)`D. `MnO_(4)^(2-)`

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