1.

The equivalent weight of phosphoric acid `(H_(3)PO_(4))` in the reaction `NaOH+H_(3)PO_(4) rarr NaH_(2)PO_(4)+H_(2)O` isA. `25`B. `98`C. `59`D. `49`

Answer» Correct Answer - B
Molecular weight of `H_(3)PO_(4)` is `98` and change in its valency `=1` equivalent wieght of `H_(3)PO_(4)`
`=("Molecular weight")/("change in valency")=(98)/(1)=98`


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