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The error in the measurement of radius of a sphere in `+-4%` What would be the error in volume of the sphere? |
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Answer» Correct Answer - `+-12%` Here, `(Deltar)/(r ) = +-4%` As volume `V = (4)/(3) pi r^3` `:. (DeltaV)/(V) =+-3((Deltar)/(r )) = +-3xx4% = +-12%` |
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