1.

The error in the measurement of radius of a sphere in `+-4%` What would be the error in volume of the sphere?

Answer» Correct Answer - `+-12%`
Here, `(Deltar)/(r ) = +-4%`
As volume `V = (4)/(3) pi r^3`
`:. (DeltaV)/(V) =+-3((Deltar)/(r )) = +-3xx4% = +-12%`


Discussion

No Comment Found