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The error in the measurement of the diameter of a sphere is 2%. What is the percentage error in the measurement of its volume?A. `4%`B. `6%`C. `8%`D. `10%` |
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Answer» Correct Answer - b `V=(4)/(3)pir^(3)=(4)/(3)pi((d)/(2))^(3)=(4)/(3)pi(d^(3))/(8)=(1)/(6)pid^(3)` As `(1)/(6)` and `pi` are constants. `therefore (deltaV)/(V)xx100=3((deltad)/(d))xx100=3xx2%=6%` |
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